resoudre equation second degre

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Quadratic Equation Solver

Solve equations of the form ax² + bx + c = 0

a
b
c
x² – 3x + 2 = 0

Solution

Two Real Solutions

Discriminant (Δ)

1

The discriminant (Δ = b² – 4ac) determines the nature of the roots:

  • Δ > 0: Two distinct real roots
  • Δ = 0: One real double root
  • Δ < 0: Two complex conjugate roots

Solutions

  • x₁ = 2
  • x₂ = 1

These are the values of x that satisfy the equation.

Solution Steps

  1. Equation: ax² + bx + c = 0 with a=1, b=-3, c=2
  2. Calculate discriminant: Δ = b² – 4ac = (-3)² – 4×1×2 = 9 – 8 = 1
  3. Since Δ > 0, there are two real solutions
  4. Calculate solutions: x = [-b ± √Δ] / (2a)
  5. x₁ = [3 + √1] / 2 = 4 / 2 = 2
  6. x₂ = [3 – √1] / 2 = 2 / 2 = 1